Liquid 'M' and liquid 'N' form an ideal solution. The vapour pressures of pure liquids 'M' and 'N' are 450 and 700 mmHg, respectively, at the same temperature. Then correct statement is:
(x_M - Mole fraction of 'M' in solution;
x_N - Mole fraction of 'N' in solution;
y_M : Mole fraction of 'M' in vapour phase;
y_N : Mole fraction of ‘N’ in vapour phase)

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

$(x_{M} - y_{M}) < (x_{N} - y_{N})$

$\frac{x_{M}}{x_{N}} < \frac{y_{M}}{y_{N}}$

$\frac{x_{M}}{x_{N}} = \frac{y_{M}}{y_{N}}$

$\frac{x_{M}}{x_{N}} > \frac{y_{M}}{y_{N}}$

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$P_{M}^{0} = 450 mmHg, P_{N}^{0} = 700 mmHg$
$P_{M} = P_{M}^{0} x_{M} = y_{M}^{P} T$
$\Rightarrow P_{M}^{\circ} = \frac{y_{M}}{x_{M}} (P_{T})$
$Similarly P_{N}^{0} = \frac{y_{N}}{x_{N}} (P_{T})$
$Given, P_{M}^{o} < P_{N}^{\circ}$
$\begin{matrix} \Rightarrow \frac{y_{M}}{x_{M}} < \frac{y_{N}}{x_{N}} \\ \Rightarrow \frac{y_{M}}{y_{N}} < \frac{x_{M}}{x_{N}} \end{matrix}$