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Liquid rises to a height of 2 cm in a capillary tube and the angle of contact between the solid and the
liquid is zero. If the tube is depressed more now, so that top of capillary is only 1 cm above the liquid,
then the apparent angle of contact between the solid and the liquid is

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60⁰

0⁰

30⁰

90⁰

answer is C.

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Detailed Solution

If a liquid can rise to a height h, but the tube has insufficient height $h'$ , then the angle of contact increases from $θ$ to $θ'$ given by $\frac{h}{\cos θ} = \frac{h^{'}}{\cos θ^{'}}$

Here, $h = 2 cm, h' = 1 cm, θ = 0^{0}$

$∴ \frac{2}{\cos 0^{\circ}} = \frac{1}{\cos θ'}$

$\Rightarrow \frac{2}{1} = \frac{1}{\cos θ'}$

or $\cos θ' = \frac{1}{2}$

$\Rightarrow θ' = 60^{\circ}$

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