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Liquids A and B form an ideal solution in the entire composition range. At 350 K, the vapor pressures of pure A and pure B are 7×10³ Pa and 12 × 10³ Pa, respectively. The composition of the vapor in equilibrium with a solution containing 40 mole percent of A at this temperature is

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x_A= 0.76 ; x_B= 0.24

x_A= 0.37 ; x_B= 0.63

x_A= 0.28 ; x_B= 0.72

x_A= 0.4 ; x_B= 0.6

answer is B.

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Detailed Solution

Complete Solution

Given Data:

x_A = 0.4
P_A⁰ = 7 × 10³ Pa
P_B⁰ = 12 × 10³ Pa

Total Pressure:

P = (0.4 × 7 × 10³) + (0.6 × 12 × 10³) = 10 × 10³ Pa

Mole Fraction in Vapor Phase:

x_A = (0.4 × 7 × 10³) / (10 × 10³) = 0.28

x_B = 1 - 0.28 = 0.72

Hence, correct option is: (B) X_A = 0.28 and X_B = 0.72

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