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Q.

Liquids A and B form an ideal solution in the entire composition range. At 350 K, the vapor pressures of pure A and pure B are 7×103 Pa and 12 × 103 Pa, respectively. The composition of the vapor in equilibrium with a solution containing 40 mole percent of A at this temperature is

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a

xA = 0.76 ; xB = 0.24

b

xA = 0.37 ; xB = 0.63

c

xA = 0.28 ; xB = 0.72

d

xA = 0.4 ; xB = 0.6

answer is B.

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Detailed Solution

Complete Solution

Given Data:

  • xA = 0.4
  • PA0 = 7 × 103 Pa
  • PB0 = 12 × 103 Pa

Total Pressure:

P = (0.4 × 7 × 103) + (0.6 × 12 × 103) = 10 × 103 Pa

Mole Fraction in Vapor Phase:

xA = (0.4 × 7 × 103) / (10 × 103) = 0.28

xB = 1 - 0.28 = 0.72

Hence, correct option is: (B) XA = 0.28 and XB = 0.72

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