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Liquids A and Bare at 30°C and 20°C. When mixed in equal masses, the temperature of the mixture is found to be 26°C.Their specific heats are in the ratio of:

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3 : 2

1 : 1

2 : 3

4 : 3

answer is A.

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Detailed Solution

heat lost = Heat gained
$\Rightarrow {ms}_{A} (30 - 26) = {ms}_{B} (26 - 20) \Rightarrow \frac{s_{A}}{s_{B}} = \frac{3}{2}$

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