LIST - 1                                    LIST - 2

(Molecule)                              (Pure and hybrid orbitals)

A) C₂H₆                                   1) 12, 18

B) C₂H₄                                   2) 6, 4

C) C₂H₂                                   3) 6, 6

D) C₆H₆                                   4) 6, 8

The correct match is

A  B  C  D

 ₆C¹²  =  2,4  =  1s²2s²2p²

H₁¹  =  1  = 1s

Each s subshell has 1 orbital

Each p subshell has 3 orbitals

• In C₂H₆ , every C is sp³ hybridized so there are 2 $\times$ (1s + 3p) = 2$\times$4 = 8 hybrid orbitals from C and 6 $\times$ (1s) = 6$\times$1 = 6 pure orbitals from H
• In C₂H₄ , every C is sp² hybridized so there are 2$\times$(1s + 2p) = 2$\times$3 = 6 hybrid orbitals from C and 4 $\times$(1p) = 4$\times$1 = 4 pure orbitals from H + 2$\times$(1s) = 2 pure orbitals from C = 6 pure orbitals total
• In C₂H₂ , every C is sp hybridized so there a 2 $\times$ (1s + 1p) = 2$\times$2 = 4 hybrid orbitals from C and 2 $\times$ (1s) = 2$\times$1 = 2 pure orbitals from H + 2 $\times$(2p) = 2$\times$2 = 4 pure orbitals from C = 6 pure orbitals total
• In C₂H₆ , every C is sp² hybridized so there are 6 $\times$(1s + 2p) = 6$\times$3 = 18 hybrid orbitals from C and 6 $\times$ (1s) = 6$\times$1 = 6 pure orbitals from H + 6$\times$(1p) = 6 pure orbitals from C = 12 pure orbitals total

Hence, the correct option is option (D) 4 3 2 1.