Q.

 LIST - 1 LIST - 2
A)Mole fraction(i)No. of g equivalents in 1000ml of solution
B)Molarity(ii)Always less than one
C)Normality(iii)Greater than or equal to molarity
D)Molality(iv)No. of g moles present in 1000ml solution
  (v)No. of g moles of solute 1kg of solvent
 ABCD
1iiiiiiiv
2iiiiiiv
3iiviiiii
4iiiviiiv

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a

2

b

1

c

3

d

4

answer is D.

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Detailed Solution

detailed_solution_thumbnail

(A) Sum of the Mole fractions of all the components present in the solution is equals to 'one' . Hence it is always less than one

(B) Molarity (M)= No. of gm moles present in 1000ml solution.

(C) Normality(N)= Molarity×Valence, So it is Greater than or equal to molarity.

                      = no. of g equivalents in 1000ml of solution

(D) Molality(m)= No. of gm moles of solute in 1kg of solvent.

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