List - 1	List - 2
$\text{A)}{\mathrm{OF}}_2$	$$\begin{gathered} 1) \mathrm{Tetrahedral}, \mathrm{bond} \mathrm{angle} \\ {109}^{\circ }{28}^{\text{'}} \end{gathered}$$
$\text{B)}{\left[{\mathrm{NiCN}}_4\right]}^{-2}$	$$\begin{gathered} \text{ 2)Linear, bond } \\ \text{ angle }{180}^{\circ } \end{gathered}$$
$\text{C)}{\mathbf{I}}_3^{-}$	$$\begin{gathered} \text{ 3)Square planar, } \\ \text{ bond angle }{90}^{\circ } \end{gathered}$$
$\text{D)}{\mathrm{XeF}}_4$	$$\begin{gathered} \text{ 4)Angular, bond } \\ \text{ angle }{102}^0 \end{gathered}$$

The correct match is

The bond angle is the angle made by two covalent bonds originating from a single atom. It contributes to the shape of a molecule.

${\left[Ni{\left(CN\right)}_4\right]}^{-2}$ has a square planar structure. 

Xenon Tetrafluoride bond angle is $90°$
The triiodide ion has a linear structure.
The shape of $\mathrm{F}-\mathrm{O}-\mathrm{F}$ is bent. 

So, option A) is correct.