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LIST -I LIST-II
A) R = 8.314 J. Kelvin^-1 mol^-1 1) STP conditions
B) V = 22.711 lit 2) SI unit
C) P = 1 bar;T = 273.15 K 3) CGS unit
D) R = 0.8314 x10⁸ergs. kelvin^-1 mol ^-1 4) Gram moleucular weight
5) Gram molar volume at S.T.P.

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A B C D

5 4 3 1

A B C D

4 3 2 1

A B C D

3 5 2 4

A B C D

2 5 1 3

answer is D.

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Detailed Solution

R =8.314 JK^-1mol^-1

22.41 lit is the volume occupied by any gas at STP

STP refers to the thermodynamics state of P =1 bar,T =273 K

1 J = 10⁷erg

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LIST -I	LIST-II
A) R = 8.314 J. Kelvin^-1 mol^-1	1) STP conditions
B) V = 22.711 lit	2) SI unit
C) P = 1 bar;T = 273.15 K	3) CGS unit
D) R = 0.8314 x10⁸ergs. kelvin^-1 mol ^-1	4) Gram moleucular weight
	5) Gram molar volume at S.T.P.

LIST -ILIST-IIA) R = 8.314 J. Kelvin-1 mol-11) STP conditionsB) V = 22.711 lit2) SI unitC) P = 1 bar;T = 273.15 K3) CGS unitD) R = 0.8314 x108 ergs. kelvin-1 mol -14) Gram moleucular weight 5) Gram molar volume at S.T.P.

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LIST -I LIST-II
A) R = 8.314 J. Kelvin^-1 mol^-1 1) STP conditions
B) V = 22.711 lit 2) SI unit
C) P = 1 bar;T = 273.15 K 3) CGS unit
D) R = 0.8314 x10⁸ergs. kelvin^-1 mol ^-1 4) Gram moleucular weight
5) Gram molar volume at S.T.P.