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Q.

 LIST-1                                                                            LIST - 2

A) 0.0821 lit.atmmol-1k-1                            1) Density of mercury 

B) 1.38×10-23 joule k-1 molecule-1           2) Plank's constant

C) 13.6 g cm-3                                                  3) Gram molar volume

D) 22400 ml of gas                                            4) Gas constant

                                                                                5) Boltzmann constant

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a

A-5 ; B-4 ; C-3 ; D-2

b

A-4; B-3; C-5; D-1

c

A-4; B-3; C-4; D-2

d

A-4 ; B-5 ; C-1 ; D-3

answer is D.

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Detailed Solution

Given: Two lists are given. We have to match the correct one with each other.

Concept Used: Gas Constant, Boltzmann Constant, Density, Gram molar volume.

Detailed Solution: We know that 0.0821 is the value of R i.e., Gas constant.

Hence, A-4 is correct.

Now, we also know that Boltzmann constant=RN8.3146.023×1023=1.38×10-23.

Hence, B - 5 is correct.

Now, 13.6 g cm-3  we know that g/ml is a unit of density .

Hence, C - 1 is correct.

And 22400ml is Gram molar volume.

Hence, D-3 is correct.

Therefore, option (D) is the answer.

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