LIST-1 $$                            LIST-2

A) Mole fraction             1) No.of gram equivalents in $1000 \mathrm{ml}$ of solution

B) Molarity                      2) Always less than one

C) Normality                  3) Greater than or equal to molarity

D) Molality                     4) No. of g moles present in $1000 \mathrm{ml}$ solution

                                         5) No. of g moles of solute $1 \mathrm{kg}$ of solvent 

The correct match is

We know that

Mole Fraction $=\frac{\mathrm{No}.\mathrm{of} \mathrm{moles} \mathrm{of} \mathrm{solute}}{\mathrm{Total} \mathrm{moles} \mathrm{of} \mathrm{solution}}$

And the total number of moles present in solution is always 1. So, clearly, fraction will be always less than 1.

Molarity$=\frac{\mathrm{No}. \mathrm{of} \mathrm{moles} \mathrm{of} \mathrm{solute}}{\mathrm{Volume} \mathrm{of} \mathrm{solution}(\mathrm{in} \mathrm{litres})}$

Normality$=\frac{\mathrm{No}. \mathrm{of} \mathrm{gram} \mathrm{equivalents} \mathrm{of} \mathrm{solute}}{\mathrm{Volume} \mathrm{of} \mathrm{Solution}(\mathrm{in} \mathrm{litres})}$      $(1\mathrm{l}=1000 \mathrm{ml})$

And also $\mathrm{N}=\mathrm{M}\times {\mathrm{n}}_{\mathrm{f}}$

So,$\mathrm{N}\ge \mathrm{M}$

Molality$=\frac{\mathrm{No}. \mathrm{of} \mathrm{moles} \mathrm{of} \mathrm{solute}}{\mathrm{Volume} \mathrm{of} \mathrm{solvent}(\mathrm{in} \mathrm{Kg})}$

Hence the correct order is  $\begin{array}{llll}\text{ A-2 }& \text{ B-4 }& \text{ C-3 }& \text{ D-5 }\end{array}$

Therefore, the correct option is (d).