Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8

Q.

 LIST-1 LIST-2
A)R = 8.314 J.Kelvin–1mol–1a)STP conditions
B)V = 22.711 litb)SI unit
C)P = 1 bar ; T = 273.15 Kc)CGS unit
D)R = 0.8314 x 108 ergs.kelvin–1mol–1d)Gram molecular
  e)Gram molar volume at S.T.P
 ABCD
1)edca
2)dcba
3)cebd
4)beac

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

2

b

1

c

3

d

4

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

detailed_solution_thumbnail

STANDARD VALUES

Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
 LIST-1 LIST-2A)R = 8.314 J.Kelvin–1mol–1a)STP conditionsB)V = 22.711 litb)SI unitC)P = 1 bar ; T = 273.15 Kc)CGS unitD)R = 0.8314 x 108 ergs.kelvin–1mol–1d)Gram molecular  e)Gram molar volume at S.T.P ABCD1)edca2)dcba3)cebd4)beac