List I		List II
A	s block	1	Rare Earths
B	d block	2	Noble Gases
C	f block	3	Strong Reducing agents
D	p block	4	$\left(n-1\right)s^2{p}^6{d}^{10}$
		5	present from fourth period

 

 

The correct match is

We know that s - Block elements are good reducing agents because they are electropositive in nature. Now, We also know that d - Block elements form Complex compounds due to presence of Vacant d-orbitals  in which a ligand can donate its electron. And, f - Block are Rare earths elements as they are rarely found in earth’s crust. Now, P-block elements are group 18 of the periodic table which are noble gases  except He. 

Hence, from the above conditions option( c) is the answer.