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Q.

List I (Trigonometric equation)List II(General Solution)
A)  cos2θ=5+14P) θ=nπ±π3,nz
B)  Tan2θ=3Q) θ=2nπ±π4+π6,nz
C)  2sin2θ=3cosθR)  θ=nπ±π10,nz
d)  3cosθ+sinθ=2S) θ=2nπ±π3,nz

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a

 AR,BP,CS,DQ

b

AQ,BS,CP,DR

c

AR,BQ,CP,DS

d

 AQ,BR,CQ,DP 

answer is A.

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Detailed Solution

a      cos2θ=5+14

cos2θ=cosπ5

θ=nπ±π10,nz

b      Tan2θ=3

  Tan2θ=Tan2π3

θ=nπ±π3,nz

c      2sin2θ=3cosθ

21cos2θ=3cosθ

2cos2θ+3cosθ2=0

cosθ+22cosθ1=0

cosθ=12

θ=2nπ±π3,nz

d      3cosθ+sinθ=2

32cosθ+12sinθ=12

cosθπ6=cosπ4

θπ6=2nπ±π4

θ=2nπ±π4+π6,nz

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