List I	List II
A) Ethane	2 sp carbons
B) Ethylene	$6{\mathrm{sp}}^2\text{ carbons }$
C) Acetylene	$2{\mathrm{sp}}^3\text{ carbons }$
D) Benzene	$2{\mathrm{sp}}^2\text{ carbons }$
	$1\mathrm{sp}\text{ and }1{\mathrm{sp}}^2 \mathrm{carbons}$

The correct answer is

$$\begin{gathered} \text{ (A) Ethane - has }2{\mathrm{sp}}^3\text{ carbons } \\ \text{ (B) Ethylene - has }2{\mathrm{sp}}^2\text{ carbons } \\ \text{ (C) Acetylene - has }2\mathrm{sp}\text{ carbons } \\ \text{ (D) Benzene - has }6{\mathrm{sp}}^2\text{ carbons } \end{gathered}$$

Hence, the correct option is option (A)

 $\begin{array}{llll}\text{ A }& \text{ B }& \text{ C }& \text{ D }\\ 3& 4& 1& 2\end{array}$.