Ln (Lanthanide) $\overset{with hologen}{\to} (x)$
Ln (Lanthanide) $\overset{Burn with O_{2}}{\to} (Y)$
Ln (Lanthanide) $\overset{∆ with N_{2}}{\to} (Z)$
X, Y and Z are respectively :

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$Ln X_{2}, LnO, LnN$

${LnX}_{2}, {Ln}_{2} O_{3}, {Lm}_{3} N$

$Ln X_{3}, {Ln}_{2} O_{3}, {Ln}_{3} N$

${LnX}_{3}, {Ln}_{2} O_{3}, LnN$

answer is B.

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Detailed Solution

Ln shows a common oxidation state of +3. The reaction are,

Ln (Lanthanide) $\overset{with hologen}{\to} {LnX}_{3}$

Ln (Lanthanide) $\overset{Burn with O_{2}}{\to} {Ln}_{2} O_{3}$

Ln (Lanthanide) $\overset{∆ with N_{2}}{\to} LnN$

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