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Q.

Locus of the point of intersection of perpendicular tangents drawn one to each of the circles x2+y2=8 and x2+y2=12 is

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a

x2+y2=4

b

x2+y2=20

c

x2+y2=16

d

x2+y2=208

answer is B.

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Detailed Solution

Tangents are perpendicular

Locus of point of intersection perpendicular tangents drawn to  each of the circles x2+y2=a2 and x2+y2=b2  is x2+y2=a2 +b2 So,required tangent is x2+y2=20 

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