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Q.

Logarithms of readings of pressure and volume for an ideal gas were plotted on a graph as shown in the given figure. By measuring the gradient, it can be shown that the gas may be

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a

monatomic and undergoing an isothermal change

b

triatomic and undergoing an isothermal change

c

monatomic and undergoing an adiabatic change

d

diatomic and undergoing an adiabatic change

answer is C.

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Detailed Solution

log P=m log V+C1, where C1 is positive, m is slope

m=2.382.101.11.3=1.4

logP=1.4logV+C1

log PV1.4=C1

PV1.4=k

Thus, it represents an ideal diatomic gas undergoing adiabatic change. 

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