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Lower end of a glass capillary tube of radius r is dipped in water and capillary rise is found to be 8 cm. When lower end of a glass capillary tube of radius 2r is dipped in water, capillary rise will be

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4 cm

16 cm

12 cm

2 cm

answer is A.

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Detailed Solution

$h \propto \frac{1}{r} \Rightarrow \frac{h'}{h} = \frac{r}{r'} \Rightarrow \frac{h'}{8} = \frac{r}{2 r} \Rightarrow h' = 4 cm$

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