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Q.

Ltt0(11sin2t+21sin2t+.......+n1sin2t)sin2t=

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a

n2+n

b

n

c

n(n+1)2

d

n2

answer is B.

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Detailed Solution

lLtt0(11sin2t+21sin2t+......+n1sin2t)sin2t  =ltt0(1cosec2t+2cosec2t+......+ncosec2t)sin2t    =ltt0(ncosec2t)sin2t[(1n)cosec2t+(2n)cosec2t+...+1]sin2t    =n[0+0+.....+1]0=n 

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