Ltx→06x−3x−2x+1x2=

Ltx→02x.3x−3x−2x+1x2Ltx→03x(2x−1)−1(2x−1)x2Ltx→0(2x−1)x(3x−1)xLtx→02x−1xLtx→03x−1x=loge2. loge3

Ltx→06x−3x−2x+1x2=

Ltx→02x.3x−3x−2x+1x2Ltx→03x(2x−1)−1(2x−1)x2Ltx→0(2x−1)x(3x−1)xLtx→02x−1xLtx→03x−1x=loge2. loge3

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$\underset{x \to 0}{L t} \frac{6^{x} - 3^{x} - 2^{x} + 1}{x^{2}} =$

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$(\log_{e} 2) \log_{e} 3$

$\log_{e} 5$

$\log_{e} 6$

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$\underset{x \to 0}{L t} \frac{2^{x} {.3}^{x} - 3^{x} - 2^{x} + 1}{x^{2}}$

$\underset{x \to 0}{L t} \frac{3^{x} (2^{x} - 1) - 1 (2^{x} - 1)}{x^{2}}$

$\underset{x \to 0}{L t} \frac{(2^{x} - 1)}{x} \frac{(3^{x} - 1)}{x}$

$\underset{x \to 0}{L t} \frac{2^{x} - 1}{x} \underset{x \to 0}{L t} \frac{3^{x} - 1}{x} = \log_{e}^{2} . \log_{e}^{3}$

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Ltx→06x−3x−2x+1x2=

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$\underset{x \to 0}{L t} \frac{6^{x} - 3^{x} - 2^{x} + 1}{x^{2}} =$