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Q.

Ltxπ21+cos 2xcot 3x3sin 2x-1

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a

1 3log a

b

2L3 log 3

c

13log 3

d

1log 3

answer is C.

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Detailed Solution

Ltxπ21+cos 2xcot 3x3sin 2x-1 =Ltxπ2 (1+cos2x)tan3x3sin2x-1 =Ltxπ2 2cos2x sin3xcos3x3sin2x-1sin2x sin2x =Ltxπ2 2cos2x sin3x(4cos2x-3cos x)2xin x cos x.sin2x3sin2x-1  =Ltxπ2 sin3x(4cos2x-3)sin x.sin2x3sin2x-1 =-1(0-3)1log 3=13log3

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