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Q.

Ltxπ4cosxsinx(π4x)(cosx+sinx)

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a

1

b

4

c

7

d

8

answer is A.

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Detailed Solution

Ltxπ42(12cosx12sinx)(π4x)(cosx+sinx)

Ltxπ42(sinπ4cosxcosπ4sinx)(π4x)(cosx+sinx)

Ltxπ42sin(π4x)(π4x)1cosx+sinx

=2(1cosπ4+sinπ4)=2(12)=1

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