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Lucas reagent is

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anhydrous ${AlCl}_{3}$ with conc. HCl

anhydrous ${ZnCl}_{2}$ with conc. $H_{2} {SO}_{4}$

anhydrous ${ZnCl}_{2}$ with conc. HCl

anhydrous ${CaCl}_{2}$ with conc. HCl

answer is C.

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Detailed Solution

Conc. HCl and anhydrous ${ZnCl}_{2}$ are combined to create the Lucas reagent.
Primary, secondary, and tertiary alcohols are used to categorise low molecular weight alcohols.

$ROH + HCl \overset{{ZnCl}_{2}}{⟶} RCl + H_{2} O$

Chloride ion replaces hydroxide ion in this substitution process.

Hence option C is correct

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