<math xmlns="http://www.w3.org/1998/Math/MathML"><msubsup><mi mathvariant="normal">E</mi><mi>cell</mi><mi mathvariant="normal">o</mi></msubsup><mo>&nbsp;</mo></math>of the reaction is&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mi>Zn</mi><mo>(</mo><mi mathvariant="normal">s</mi><mo>)</mo><mo>+</mo><msup><mi>Cu</mi><mrow><mn>2</mn><mo>+</mo></mrow></msup><mo>(</mo><mi>aq</mi><mo>)</mo><mo>→</mo><msup><mi>Zn</mi><mrow><mn>2</mn><mo>+</mo></mrow></msup><mfenced><mi>aq</mi></mfenced><mo>+</mo><mi>Cu</mi><mo>(</mo><mi mathvariant="normal">s</mi><mo>)</mo><mo>;</mo></math> <math xmlns="http://www.w3.org/1998/Math/MathML"><mfenced close="]" open="["><mrow><mi>If</mi><mo>&nbsp;</mo><msubsup><mi mathvariant="normal">E</mi><mrow><msup><mi>Zn</mi><mrow><mn>2</mn><mo>+</mo></mrow></msup><mo>/</mo><mi>Zn</mi></mrow><mi mathvariant="normal">o</mi></msubsup><mo>=</mo><mo>-</mo><mn>0</mn><mo>.</mo><mn>76</mn><mo>,</mo><msubsup><mi mathvariant="normal">E</mi><mrow><msup><mi>Cu</mi><mrow><mn>2</mn><mo>+</mo></mrow></msup><mo>/</mo><mi>Cu</mi></mrow><mi mathvariant="normal">o</mi></msubsup><mo>=</mo><mn>0</mn><mo>.</mo><mn>34</mn><mi mathvariant="normal">V</mi></mrow></mfenced></math>

For the cell,&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mi>Cu</mi><mfenced separators="|" close="|" open="|"><mrow><msup><mi>Cu</mi><mrow><mn>2</mn><mo>+</mo></mrow></msup><mo>∥</mo><msup><mi>Ag</mi><mo>+</mo></msup></mrow></mfenced><mi>Ag</mi><mo>,</mo><msubsup><mi mathvariant="normal">E</mi><mtext>cell&nbsp;</mtext><mo>∘</mo></msubsup><mo>=</mo><mo>+</mo><mn>0</mn><mo>.46</mo><mi mathvariant="normal">V</mi></math>&nbsp;If concentration of Cu2+ ions is doubled, then&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><msubsup><mi mathvariant="normal">E</mi><mi>cell</mi><mi mathvariant="normal">o</mi></msubsup></math>&nbsp;will be

A button cell used in watches function as following.<math xmlns="http://www.w3.org/1998/Math/MathML"><mi>Zn</mi><mfenced><mi mathvariant="normal">s</mi></mfenced><mo>+</mo><msub><mi>Ag</mi><mn>2</mn></msub><mi mathvariant="normal">O</mi><mfenced><mi mathvariant="normal">s</mi></mfenced><mo>+</mo><msub><mi mathvariant="normal">H</mi><mn>2</mn></msub><mi mathvariant="normal">O</mi><mfenced><mi mathvariant="normal">l</mi></mfenced><mo>⇌</mo><mn>2</mn><mi>Ag</mi><mfenced><mi mathvariant="normal">s</mi></mfenced><mo>+</mo><msup><mi>Zn</mi><mrow><mn>2</mn><mo>+</mo></mrow></msup><mfenced><mi>aq</mi></mfenced><mo>+</mo><mn>2</mn><msup><mi>OH</mi><mo>-</mo></msup><mfenced><mi>aq</mi></mfenced></math>If half cell potentials are<math xmlns="http://www.w3.org/1998/Math/MathML"><msup><mi>Zn</mi><mrow><mn>2</mn><mo>+</mo></mrow></msup><mfenced><mi>aq</mi></mfenced><mo>+</mo><mn>2</mn><msup><mi mathvariant="normal">e</mi><mo>−</mo></msup><mo>→</mo><mi>Zn</mi><mfenced><mi mathvariant="normal">s</mi></mfenced><mo>;</mo><mo>&nbsp;</mo><msup><mi mathvariant="normal">E</mi><mn>0</mn></msup><mo>=</mo><mo>−</mo><mn>0</mn><mo>.76</mo><mo>&nbsp;</mo><mi mathvariant="normal">V</mi><mspace linebreak="newline">&nbsp;</mspace><msub><mi>Ag</mi><mn>2</mn></msub><mi mathvariant="normal">O</mi><mfenced><mi mathvariant="normal">s</mi></mfenced><mo>+</mo><msub><mi mathvariant="normal">H</mi><mn>2</mn></msub><mi mathvariant="normal">O</mi><mfenced><mi mathvariant="normal">l</mi></mfenced><mo>+</mo><mn>2</mn><msup><mi mathvariant="normal">e</mi><mo>−</mo></msup><mo>→</mo><mn>2</mn><mi>Ag</mi><mfenced><mi mathvariant="normal">s</mi></mfenced><mo>+</mo><mn>2</mn><msup><mi>OH</mi><mo>-</mo></msup><mfenced><mi>aq</mi></mfenced><mo>,</mo><mo>&nbsp;</mo><msup><mi mathvariant="normal">E</mi><mn>0</mn></msup><mo>=</mo><mn>0</mn><mo>.34</mo><mo>&nbsp;</mo><mi mathvariant="normal">V</mi></math>The cell potential will be

Which of the following is an oxide(s) of iron that would be obtained on the prolonged reaction of iron with steam? <pstyle="margin-top:0pt;margin-bottom:0pt;line-height:normal;font-size:12pt"><spanstyle="font-family:'TimesNewRoman';-aw-import:ignore"><spanstyle="font-family:'TimesNewRoman';-aw-import:spaces"><pstyle="margin-top:0pt;margin-bottom:0pt;line-height:normal;font-size:12pt"><spanstyle="font-family:'TimesNewRoman';-aw-import:ignore">

Deduce from the following&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><msup><mi mathvariant="normal">E</mi><mo>⊝</mo></msup></math>values&nbsp;of half cells, what combination of two half cells would results in a cell with&nbsp;the largest potential ?<math xmlns="http://www.w3.org/1998/Math/MathML"><mi mathvariant="normal">I</mi><mo>.</mo><mo>&nbsp;</mo><mi mathvariant="normal">A</mi><mo>+</mo><msup><mi mathvariant="normal">e</mi><mo>-</mo></msup><mo>→</mo><msup><mi mathvariant="normal">A</mi><mo>⊝</mo></msup><mo>,</mo><mo>&nbsp;</mo><msup><mi mathvariant="normal">E</mi><mo>⊝</mo></msup><mo>=</mo><mo>-</mo><mn>0</mn><mo>.</mo><mn>24</mn><mo>&nbsp;</mo><mi mathvariant="normal">V</mi><mspace linebreak="newline">&nbsp;</mspace><mi>II</mi><mo>.</mo><mo>&nbsp;</mo><msup><mi mathvariant="normal">B</mi><mo>⊝</mo></msup><mo>+</mo><msup><mi mathvariant="normal">e</mi><mo>-</mo></msup><mo>→</mo><msup><mi mathvariant="normal">B</mi><mrow><mn>2</mn><mo>-</mo></mrow></msup><mo>,</mo><mo>&nbsp;</mo><msup><mi mathvariant="normal">E</mi><mo>⊝</mo></msup><mo>=</mo><mo>+</mo><mn>1</mn><mo>.</mo><mn>25</mn><mi mathvariant="normal">V</mi><mspace linebreak="newline">&nbsp;</mspace><mi>III</mi><mo>.</mo><mo>&nbsp;</mo><msup><mi mathvariant="normal">C</mi><mo>⊝</mo></msup><mo>+</mo><mn>2</mn><msup><mi mathvariant="normal">e</mi><mo>-</mo></msup><mo>→</mo><msup><mi mathvariant="normal">C</mi><mrow><mn>3</mn><mo>-</mo></mrow></msup><mo>;</mo><mo>&nbsp;</mo><msup><mi mathvariant="normal">E</mi><mo>⊝</mo></msup><mo>=</mo><mo>−</mo><mn>1</mn><mo>.</mo><mn>25</mn><mi mathvariant="normal">V</mi><mspace linebreak="newline">&nbsp;</mspace><mi>IV</mi><mo>.</mo><mo>&nbsp;</mo><mi mathvariant="normal">A</mi><mo>+</mo><mn>2</mn><msup><mi mathvariant="normal">e</mi><mo>-</mo></msup><mo>→</mo><msup><mi mathvariant="normal">D</mi><mrow><mn>2</mn><mo>-</mo></mrow></msup><mo>&nbsp;</mo><mo>&nbsp;</mo><mo>;</mo><msup><mi mathvariant="normal">E</mi><mo>⊝</mo></msup><mo>=</mo><mo>+</mo><mn>0</mn><mo>.</mo><mn>68</mn><mi mathvariant="normal">V</mi></math>

Lyophilic sols are :

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material