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M and N can complete a job in 3 and 6 hours respectively. If they work alternatively for 1 hour each, with M starting the job, then when will the job be completed.

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3 hrs

$4 \frac{1}{2}$ hrs

4 hrs

2 hrs

answer is B.

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Detailed Solution

M can complete the job in 3 hours

N can complete the job in 6 hours

So if they work alternatively for 1 hour each

LCM of 3, 6 = 18 units

$\frac{2 h r}{9 u n i t s} = \frac{?}{18 u n i t s}$

= ? = 4 hrs They will complete

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