Λm0 for NH4Cl, NaOH and NaCl are 130,248 and 126.5 ohm-1 cm2 mol-1 respectively. The Λm0 of NH4OH will be

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$Λ_{m}^{0}$ for NH₄Cl, NaOH and NaCl are 130,248 and 126.5 ohm^-1 cm² mol^-1 respectively. The $Λ_{m}^{0}$ of NH₄OH will be

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504.5

251.5

130

244.5

answer is A.

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Detailed Solution

$\land_{m}^{0} [{NH}_{4} OH] = \land_{m}^{0} [{NH}_{4} Cℓ] - \land_{m}^{0} [NaCl] + \land_{m}^{0} [{NH}_{4} OH]$
= 130 + 248 – 126.5
= 251.5 ohm^-1 cm² mol^-1

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