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Q.

Magnetic field at the centre of a current carrying circular coil is ‘B’. Now the coil is bent at right angles at diametrically opposite points P and Q as shown in figure. Then magnetic induction at the centre O is 

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a

B2

b

B22

c

2 B

d

B42

answer is A.

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Detailed Solution

At the centre of a circular coil, B=μ0i2R

Now, B1=B2=μ0i4R=B2

∴ B'=B12+B22=(B2)2+(B2)2=B2

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