Magnetic field in a plane electromagnetic wave is given by $\overrightarrow{\mathrm{B}}={\mathrm{B}}_0\sin \left(\mathrm{kx}+\mathrm{\omega t}\right)\hat{\mathrm{j}}\mathrm{T}$. Expression for corresponding electric field will be: (where $c$ is speed of light.)

Given: $\overrightarrow{\mathrm{B}}={\mathrm{B}}_0\sin \left(\mathrm{kx}+\mathrm{\omega t}\right)\hat{\mathrm{j}} \mathrm{T}$

The relation between electric and magnetic field is,

$\mathrm{c}=\frac{\mathrm{E}}{\mathrm{B}}$ or $\mathrm{E}=\mathrm{cB}$ $\Rightarrow {\mathrm{E}}_0={\mathrm{cB}}_0$

$\hat{\mathrm{E}}=\hat{\mathrm{B}}\times \widehat{\mathrm{c} }=\hat{\mathrm{j}}\times \left(-\widehat{\mathrm{i} }\right)=\hat{\mathrm{k}}$

The electric field component is perpendicular to the direction of propagation and the direction of a magnetic field. Therefore, the electric field component along $z-$axis is obtained as $\overrightarrow{\mathrm{E}}={\mathrm{cB}}_0 \sin \left(\mathrm{kx}+\mathrm{\omega t}\right)\hat{\mathrm{k}} \mathrm{V}/\mathrm{m}$.