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Q.

Magnetic field induction at centre of circular coil of radius 5 cm and carrying a current 0.9A is (in S.I.units) ( $\in_{0} =$ absolute permittivity of air S.I. units, velocity of light $= 3 \times 10^{8} m / s$ )

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a

$\frac{10^{16}}{\in_{0}}$

b

$\frac{\in_{0}}{10^{16}}$

c

$10^{16} \in_{0}$

d

$\frac{1}{\in_{0} 10^{16}}$

answer is A.

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Detailed Solution

$r = 5 \times 10^{- 2} m, i = 0.9 A, B = ?,$
$C = 3 \times 10^{8} m / s; B = \frac{μ_{0} i}{2 r} = \frac{1}{\in_{0} 10^{16}}$

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Magnetic field induction at centre of circular coil of radius 5 cm and carrying a current 0.9A is (in S.I.units) (∈0= absolute permittivity of air S.I. units, velocity of light = 3×108 m/s )