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Q.

Magnetic field strength at the centre of regular pentagon made of a conducting wire of uniform cross section area as shown in figure is :

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a

Zero even if the current ‘i’ leaves point D instead of point E

b

5μ0i4πa2sin722

c

μ0iπa2sin722

d

Not zero if current ‘i’ leaves D point instead of E

answer is D.

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Detailed Solution

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BAB=BBC=BCD=BDE=BEA  and i1i2=14

Becomes from V = IR

from above results BABCDE=BAE

So     Bcentre =0

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