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Magnetic flux $ϕ$ (in weber) linked with a closed circuit of resistance 10 ohm varies with time t (in seconds) as $ϕ = 5 t^{2} - 4t + 1$ . The induced electromotive force in the circuit at t = 0.2 sec is

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- 2.0 volts

2.0 volts

0.4 volts

- 0.4 volts

answer is D.

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Detailed Solution

ϕ = 5 t^{2} - 4 t + 1

$e = \frac{- d ϕ}{dt} = - 10 t + 4$

$but t = 0.2$

$so, e = 2 volts$

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