Magnetic flux in a circular coil of resistance $10 Ω$ changes with time as shown in figure. Direction of magnetic field is perpendicular to paper inwards.
Match the following table.
Table-1
Table-2
(A) At 1 s induced current is (P)
Clockwise
(B) At 5 s induced current is (Q)
Anticlockwise
(C) At 9 s induced current is (R)
Zero
(D) At 15 s induced current is (S)
2A
(T)
None

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$(A) - Q, S (B) - Q, R, (C) - P, R, (D) - P, S$

$(A) - Q, S (B) - P, R, (C) - P, R, (D) - Q, S$

$(A) - P, S (B) - Q, R, (C) - S, R, (D) - Q, S$

$(A) - Q, S (B) - R, (C) - P, S, (D) - Q, S$

answer is C.

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Detailed Solution

At 1 s, inward magnetic field is increasing. Hence, induced current will produce outward magnetic field. Therefore, induced current is anticlockwise.At 5 s, flux is constant. Hence, induced current is zero. At 9 s, outward magnetic field is increasing. Hence, induced current will produce inward magnetic field. Or the induced current is clockwise.

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Table-1		Table-2
(A)	At 1 s induced current is	(P)	Clockwise
(B)	At 5 s induced current is	(Q)	Anticlockwise
(C)	At 9 s induced current is	(R)	Zero
(D)	At 15 s induced current is	(S)	2A
		(T)	None