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Magnetic moment 2.84 B.M. is given by :
(At. nos. Ni = 28, Ti = 22, Cr = 24, Co = 27)

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Co²⁺

Ti³⁺

Ni²⁺

Cr²⁺

answer is D.

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Detailed Solution

Ni²⁺ = 3d⁸ =

number of unpaired electrons (r) in Ni²⁺= 2
$∵ μ = \sqrt{n (n + 2)} = \sqrt{2 (2 + 2)} = \sqrt{8} = 2 .8 BM$
Hence $μ$ = 2.8 B.M., thus Ni²⁺ is paramagnetic

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