Magnetic moment of the complex Fe(CN)6−3 approximately is

Book Online Demo

Check Your IQ

Try Test

Courses

Offline Centres

Magnetic moment of the complex ${[Fe (CN)_{6}]}^{- 3}$ approximately is

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

4.89 BM

1.73 BM

5.92 BM

2.84 BM

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

In ${[Fe (CN)_{6}]}^{- 3}$

The O. State of Fe is +3

Electronic configuration is $[Ar] 3 d^{5}$

${CN}^{-}$ is strong field ligand ,there will be the pairing of electrons and only one electron will be unpaired.

n =1

Magnetic moment = $\sqrt{n (n + 2)} = \sqrt{1 (1 + 2)} = \sqrt{3}$ =1.732M

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE