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Q.

Magnification is the ratio between height of the image to height of the object i.e.,m=heightofimageheightofobject=vu

i)If ‘m’ is +ve the image is virtual and erect.

Ii) If ‘m’ is ve the image is real and inverted.

iii)Ifm>1 , image is bigger than the object.

iv) m<1 image is smaller than the object.

v)Ifm=1 image size is equal to object size.

vi)Magnification can also be written as m=imagedistanceobjectdistance

A 1 cm object is placed perpendicular to the principal axis of a convex mirror of focal length 7.5 cm. Then the object should be placed infront of the mirror at a distance to get the size of the image as 0.6 cm is

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a

3 cm

b

5 cm

c

7.5 cm

d

10 cm

answer is B.

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Detailed Solution

Question Image

Given that for a convex mirror

f = + 7.5 cm

size of object = 1 cm

size of image = 0.6 cm

we get m=sizeofimagesizeofobject=0.61=35

(Since we are using convex mirror m should be +ve because it always form virtual images)

m=+35=vu

v=3u5 , u = ?, f = + 7.5 cm

We know 1f=1u+1v

17.5=1u+1(3u/5)

215=1u53u=353u

215=23u                                       

3u=15

u=5cm

So object should be placed infront of convex mirror at a distance of 5 cm.

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