Magnitude of enthalpy of neutralization is minimum for

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$HCl + {NH}_{4} OH$

$HCN + {NH}_{4} OH$

$HCl + KOH$

$HCN + KOH$

answer is D.

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Detailed Solution

When one mole of acid is neutralized by one mole of base, heat of neutralization is released. Its value is $57 kJ / mol$ for strong acid-strong base neutralization. Its value is less than this value for weak acids or bases. Therefore, for $HCN + {NH}_{4} OH$ , the heat of neutralization will be at its lowest.

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