Major products formed when is treated with ${\mathrm{Br}}_2$ in the presence of ${\mathrm{FeBr}}_3$

${\mathrm{CH}}_3$ group which shows +I effect due to which electron density increases on benzene ring at ortho and para position because it is it -o, p directing in nature. So in above reaction bromine should come at ortho or para position to ${\mathrm{CH}}_3$ . In option 1 & 2 Br ion comes in between both ${\mathrm{CH}}_3$ group due to which steric hindrance increases and in option 4 Br comes on meta position which is not possible.