Q.

Make a diagram to show how hypermetropia is corrected. The near point of a hypermetropic eye is 1 m. What is the power of the lens required to correct this defect? Assume that the near point of the normal eye is 25 cm

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Detailed Solution

a) Hypermetropia is also known as far-sightedness. A person with hypermetropia can see distant objects clearly but cannot see nearby objects distinctly. The near point, for the person, is farther away from the normal near point (25 cm). Such a person has to keep a reading material much beyond 25 cm from the eye for comfortable reading. This is because the light rays from a close by object are focused on a point behind the retina.

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This defect arises either because 

(i) The focal length of the eye lens is too long, or 

(ii) The eyeball has become too small. 

This defect can be corrected by using a convex lens of appropriate power.

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