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Q.

Manganate ion in acidic (or) neutral medium disproportionates to give

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a

${MnO}_{4}^{-} and {MnO}_{2}$

b

${MnO}_{2} and {Mn}_{2} O_{7}$

c

${MnO}_{4}^{-} and {Mn}^{2 +}$

d

${MnO}_{4}^{-} and {Mn}_{2} O_{3}$

answer is A.

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Detailed Solution

${MnO}_{4}^{2 -} \overset{H^{+}}{⟶} {MnO}_{4}^{-} + {MnO}_{2}$

(+6) (+7) (+4)

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