Q.

Manganese dioxide (MnO2) reacts with hydrochloric acid (HCl) to produce magnesium chloride (MgCl2), water (H2O), and chlorine (Cl2) gas. The chemical equation involved in the reaction is given as:

MnO2 + 4 HCl → MnCl2 + 2 H2O + Cl2

Which of the following substances is reduced in the given reaction?

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a

MnO2

b

MnCl2

c

HCl

d

H2O

answer is C.

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Detailed Solution

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Understanding Redox Reactions

  • Oxidation: A substance loses electrons, gains oxygen, or loses hydrogen.
  • Reduction: A substance gains electrons, loses oxygen, or gains hydrogen.

Step-by-Step Analysis of the Reaction

  1. Reactants and Products:
    • MnO2: Manganese dioxide.
    • HCl: Hydrochloric acid.
    • Products: MnCl2, H2O, and Cl2.
  2. Role of MnO2:
    • MnO2 starts as manganese dioxide, which contains manganese in a +4 oxidation state.
    • In MnCl2, manganese transitions to a +2 oxidation state.
    • The reduction of MnO2 occurs because it loses oxygen during the reaction, thereby gaining electrons.
  3. Reduction Process:

    The loss of oxygen from MnO2 results in the formation of MnCl2. This loss of oxygen qualifies MnO2 as the reduced substance in this redox reaction.

  4. Oxidation Process (for comparison):

    HCl is oxidized as chlorine in Cl2 changes from -1 to 0 oxidation state.

Key Takeaway

In this reaction:

  • Reduced Substance: MnO2 (loses oxygen to form MnCl2).
  • Oxidized Substance: HCl (chlorine is oxidized to form Cl2).

Hence, the correct answer is MnO2.

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