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Q.
Manganese dioxide (MnO2) reacts with hydrochloric acid (HCl) to produce magnesium chloride (MgCl2), water (H2O), and chlorine (Cl2) gas. The chemical equation involved in the reaction is given as:
MnO2 + 4 HCl → MnCl2 + 2 H2O + Cl2
Which of the following substances is reduced in the given reaction?
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a
MnO2
b
MnCl2
c
HCl
d
H2O
answer is C.
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Detailed Solution

Understanding Redox Reactions
- Oxidation: A substance loses electrons, gains oxygen, or loses hydrogen.
- Reduction: A substance gains electrons, loses oxygen, or gains hydrogen.
Step-by-Step Analysis of the Reaction
- Reactants and Products:
- MnO2: Manganese dioxide.
- HCl: Hydrochloric acid.
- Products: MnCl2, H2O, and Cl2.
- Role of MnO2:
- MnO2 starts as manganese dioxide, which contains manganese in a +4 oxidation state.
- In MnCl2, manganese transitions to a +2 oxidation state.
- The reduction of MnO2 occurs because it loses oxygen during the reaction, thereby gaining electrons.
Reduction Process:
The loss of oxygen from MnO2 results in the formation of MnCl2. This loss of oxygen qualifies MnO2 as the reduced substance in this redox reaction.
Oxidation Process (for comparison):
HCl is oxidized as chlorine in Cl2 changes from -1 to 0 oxidation state.
Key Takeaway
In this reaction:
- Reduced Substance: MnO2 (loses oxygen to form MnCl2).
- Oxidized Substance: HCl (chlorine is oxidized to form Cl2).
Hence, the correct answer is MnO2.