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In a constant acceleration motion along a straight line distance covered must be equal to displacement.

For uniform velocity motion, average acceleration of particle is non-zero.

For accelerated motion, $\bar{a} . \bar{v} > 0$ ,where a and v are acceleration and velocity of the particle.

For decelerated motion, $\bar{a} . \bar{v} > 0$ ,where a and v are acceleration and velocity of the particle.

answer is B.

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Detailed Solution

For uniform velocity motion, average acceleration of particle is zero since velocity is constant.

For accelerated motion, $\bar{a} . \bar{v} > 0$ ,where a and v are acceleration and velocity of the particle because both acceleration and velocity are positive.

For decelerated motion, $\bar{a} . \bar{v} < 0$ ,where a and v are acceleration and velocity of the particle. because if velocity is positive, acceleration will be negative since it opposes the motion.

In a constant acceleration motion, distance covered need not be equal to displacement. In case of acceleration of a body being in the opposite direction of the initial velocity of the body, distance covered will be greater than the displacement.

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