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Like other light nuclei the $_{2}^{4} He$ also have a low value of the binding energy per nucleon

The BE per nucleon decreases for nuclei with small as well as large atomic

energy required to remove one neutron from $_{3}^{7} Li$ to transform it into $_{3}^{6} Li$ is 5.6 MeV so, BE per nucleon of $_{3}^{6} Li$ is also 5.6 MeV

When two deuterium nuclei fuse together, they give rise to tritium nucleus

answer is B.

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Detailed Solution

Option (1) is incorrect, $_{2}^{4} He$ is a more stable species among its neighbours due to its high BE per nucleon.

$_{1}^{2} H +_{1}^{2} H ⟶_{1}^{3} H +_{1}^{1} p$

Option (4) is not possible as nucleon number is not conserved.

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