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Mars has a diameter of approximately $0.5$ of that of earth, and mass of $0.1$ of that of earth. The surface gravitational field strength on mars as compared to that on earth is a factor of-

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$0.2$

$0.4$

$2.0$

$0.1$

answer is D.

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Detailed Solution

$g = \frac{G M_{e}}{{R_{e}}^{2}} g_{m a r s} = \frac{G (0.1) M_{e}}{{(0.5)}^{2} {R_{e}}^{2}} = \frac{0.4 G M_{e}}{{R_{e}}^{2}} = 0.4 g$

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