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Mass in grams of copper deposited by passing 10 A current through a voltmeter containing copper sulphate solution for 100 seconds is [ molar mass of Cu = 63 g mol^-1]

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3.26 g

0.326 g

32.6 g

0.0326 g

answer is B.

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Detailed Solution

$m_{Cu} = \frac{At. wt \times C \times t}{Valency \times 96500} = \frac{63 \times 10 \times 100}{2 \times 96500}$
= 0.326 g

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