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Q.

Mass number of thorium is A = 232 and the atomic number is Z=90. After disintegration to last element Pb is obtained which has A = 208 and Z = 82. In this process the number of emitted 'α' and 'β' particles are

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a

4 and 6

b

6 and 4

c

3 and 2

d

2 and 3

answer is C.

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Detailed Solution

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α=232−2084=6β=2×6−90−82=4

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