Mass numbers of two nuclei are in the ratio of 4 : 3. Their nuclear densities will be in the ratio of

Radius of nucleus    $\mathrm{R}={\mathrm{R}}_0{\mathrm{A}}^{\frac{1}{3}}$

$\text{ Density of nucleus }=\frac{\text{ Mass of nucleus }}{\text{ volume of nucleus }}$

$\mathrm{\rho }=\frac{\mathrm{m}\times \mathrm{A}}{\frac{4}{3}{\mathrm{\pi R}}^3}$   Where m : mass of proton or neutron

$$\begin{gathered} \mathrm{\rho }=\frac{\mathrm{m}\times \mathrm{A}}{\frac{4}{3}{{\mathrm{\pi R}}_0}^3\mathrm{A}} \\ \mathrm{\rho }\propto {\mathrm{A}}^0 \end{gathered}$$

Hence density of nucleus is independent of mass number