Mass of ethylene glycol (antifreeze) to be added to 18.6 kg of water to protect the freezing point at $- 24^{o} C$ is ________________kg (Molar mass in g $m o l^{- 1}$ for ethylene glycol 62,
$K_{f}$ of water=1.86 K $k g m o l^{- 1}$ )

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11.234

20.125

8.692

14.880

answer is B.

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Detailed Solution

$Δ T_{f} = K_{b} m$
$m = \frac{W_{(s o l u t e)}}{M_{(s o l u t e)}} \frac{1}{W_{(s o l v e n t)}}$
$\Rightarrow 24 = 1.86 \times \frac{x}{62} \times \frac{1}{18.6} = 14880 g = 14.88 k g$

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