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Q.

Mass percent of Na in ${Na}_{2} {CO}_{3}$ is

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a

$31.20 %$

b

$43.40 %$

c

$38.20 %$

d

$21.52 %$

answer is D.

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Detailed Solution

Mass per cent of $Na = \frac{2 M_{Na}}{M_{{Na}_{2} {CO}_{3}}} \times 100 = \frac{46}{106} \times 100 % = 43.40 %$

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