Mass ratio of two particles ‘A’ to ‘B’ is 3 : 1. If the velocity of particle ‘A’ is 2×104 m/s and that of particle ‘B’ is 6×104 m/s then the ratio of de Broglie wavelength of ‘A’ to ‘B’ is

de Broglie equation;λ=hmv; h is a constant; λAλB=mBvBmAvA; λAλB=16×10432×104; λAλB=11;

Mass ratio of two particles ‘A’ to ‘B’ is 3 : 1. If the velocity of particle ‘A’ is 2×104 m/s and that of particle ‘B’ is 6×104 m/s then the ratio of de Broglie wavelength of ‘A’ to ‘B’ is

de Broglie equation;λ=hmv; h is a constant; λAλB=mBvBmAvA; λAλB=16×10432×104; λAλB=11;

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Mass ratio of two particles ‘A’ to ‘B’ is 3 : 1. If the velocity of particle ‘A’ is $2 \times 10^{4} m / s$ and that of particle ‘B’ is $6 \times 10^{4} m / s$ then the ratio of de Broglie wavelength of ‘A’ to ‘B’ is

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1 : 6

6 : 1

1 : 1

3 : 2

answer is C.

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de Broglie equation;

$λ = \frac{h}{mv}; h is a constant; \frac{λ_{A}}{λ_{B}} = \frac{m_{B} v_{B}}{m_{A} v_{A}}; \frac{λ_{A}}{λ_{B}} = \frac{1 (6 \times 10^{4})}{3 (2 \times 10^{4})}; \frac{λ_{A}}{λ_{B}} = \frac{1}{1};$

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Mass ratio of two particles ‘A’ to ‘B’ is 3 : 1. If the velocity of particle ‘A’ is 2×104 m/s and that of particle ‘B’ is 6×104 m/s then the ratio of de Broglie wavelength of ‘A’ to ‘B’ is

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Mass ratio of two particles ‘A’ to ‘B’ is 3 : 1. If the velocity of particle ‘A’ is $2 \times 10^{4} m / s$ and that of particle ‘B’ is $6 \times 10^{4} m / s$ then the ratio of de Broglie wavelength of ‘A’ to ‘B’ is