Match appropriately the column-1 with column-2 :Column - 1Column -2(a)Electric field of a point charge is proportional to _ at any point.(p)1r(b)Electric field of a short electric dipole is proportional to _ at any point.(q)1r2(c)Electric field of linear charge distribution is proportional to _ at any point.(r)1r3

Electric field due to point charge= Kqr2Electric field due to electric dipole= Kpcosθr3Electric field due to linear charge distribution= λ2πεor

Match appropriately the column-1 with column-2 :Column - 1Column -2(a)Electric field of a point charge is proportional to _ at any point.(p)1r(b)Electric field of a short electric dipole is proportional to _ at any point.(q)1r2(c)Electric field of linear charge distribution is proportional to _ at any point.(r)1r3

Electric field due to point charge= Kqr2Electric field due to electric dipole= Kpcosθr3Electric field due to linear charge distribution= λ2πεor

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Match appropriately the column-1 with column-2 :
Column - 1 Column -2
(a) Electric field of a point charge is proportional to _ at any point. (p) $\frac{1}{r}$
(b) Electric field of a short electric dipole is proportional to _ at any point. (q) $\frac{1}{r^{2}}$
(c) Electric field of linear charge distribution is proportional to _ at any point. (r) $\frac{1}{r^{3}}$

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a - p, b - q, c - r

a - r, b - p, c - q

a - q, b - r, c - p

a - r, b - q, c - p

answer is A.

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Detailed Solution

Electric field due to point charge= $\frac{K q}{r^{2}}$

Electric field due to electric dipole= $\frac{K p \cos θ}{r^{3}}$

Electric field due to linear charge distribution= $\frac{λ}{2 {πε}_{o} r}$

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